A Conversation for Ask h2g2

42!

Post 21

Peregrin

D'oh! Why didn't I see that!!!

Do you watch Countdown a lot btw? smiley - winkeye


42!

Post 22

Cloviscat

Not now I work for a living! smiley - winkeye


42!

Post 23

Argon0 (50 and feeling it - back for a bit)

ditto!

Just realised that by using Inv Tan you can get Mark Moxon's (U13) to work

Thus

INvTan(1) - 3 = 42.

So he can stay then...


42!

Post 24

Gullibility Personified

Can a law be made stating that any number will, given the correct processes, turn into 42?


42!

Post 25

Galaxy Babe - eclectic editor

smiley - laugh@Cloviscat.
I was just going to type that to Peregrin when I spotted your answer underneath.
Hehehehe
Are we all getting expert mathematicians or what?
smiley - biggrin


42!

Post 26

Gnomon - time to move on

Since when has 0^0 been 1? I think you are pulling the wool over our eyes here, like in those proofs that 1 = 2.


42!

Post 27

Argon0 (50 and feeling it - back for a bit)

Anything to the power of 0 is 1 - including 0 (just asked my Brother (University Lecturer in Maths) and he concurs). Theoretically you could use it to prove that anything equals anything else (numerically) and thus that Black is White (e.g. Black is No. (smiley - erm hang on while I look this up.....) 000000 on the Web and White is FFFFFF - so 000000^0 = 1 and FFFFFF^0=1 so Black=White .... Oh Sh*t where'd that 10 tonne truck come from ..... aaaaarrrrrgh.....).


42!

Post 28

Gullibility Personified

That is strange! Although it makes a lot more sense the way you explaing it than it will when my m***s teacher tries to...*wince*

But maths isn't that bad...I guess...go read "The Parrot's Theorum".


42!

Post 29

HenryS

I reckon 0^0 is undefined - yeah 0^anything is 1, but also anything^0 is 0. So if you're ranging over x and y looking at the value of x^y you get a discontinuity at (x,y) = (0,0).

Whoever researcher 2 is ('Nobody' it seems...), I can do theirs:

-log(log(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(sqrt(e))))))))))))))))))))))))))))))))))))))))))))/log(2) = 42.

(That'd better be natural log by the way)


42!

Post 30

Galaxy Babe - eclectic editor

smiley - yikes


42!

Post 31

NMcCoy (attempting to standardize my username across the Internet. Formerly known as Twinkle.)

Anything ^0 is 1. Take this for example.
10^3 = 1000
10^2 = 100
10^1 = 10
10^0 = 1
10^-1= 0.1
10^-2= 0.01
10^-3= 0.001

...and so on. It works with other numbers, but 10 is the "cleanest" because we use base 10.


42!

Post 32

NMcCoy (attempting to standardize my username across the Internet. Formerly known as Twinkle.)

Um, 153916? What can you do with that?


42!

Post 33

Gnomon - time to move on

Anything to the power of 0 is 1, except 0^0. The reason it is an exception is that 0 to the power of anything is 0.

You can approach this problem from two different directions:

10^0 = 1
1^0 = 1
0.1^0 = 1
0.01^0 = 1

and so on. This would lead you to believe that 0^0 = 1.

But:

0^10 = 0
0^1 = 0
0^0.1 = 0
0^0.01 = 0

and so on. This would lead you to believe that 0^0 = 0.

Mathematicians get around this by saying that 0^0 is "undefined". It does not have a value. It is one use of the "^" symbol which is forbidden.


42!

Post 34

HenryS

(1+5)x(3+9+1-6) = 42


42!

Post 35

Gnomon - time to move on

1-5-1+50-3

Is there a prize for using only + and - ?


42!

Post 36

The Jester (P. S. of Village Idiots, Muse of Comedians, Keeper of Jokes, Chef and Seraph of Bad Jokes) LUG @ A458228

Here's one for Abi:

- log (base 2) 8 + artan 1 = -3+45=42!!!

And for myself:

-5 - 5 + 7 + ( 9 * 5 ) = -3 + 45 = 42!!!

38-J

JOTD: A friend in need is a fiend indeed.


42!

Post 37

Argon0 (50 and feeling it - back for a bit)

Yeah, OK after talking to my Bro again this past w/e, I have to concur that there are two possible values of 0^0 - 0 and 1.

Both are valid, in a similar way to sqrt(x) having two values (e.g. sqrt(4) = ±2 (2 or -2)) This is because -2 * -2 = 4 and 2 * 2 =4. This is true of any "even" root (e.g. 4th root of 16 = 2 or -2) as the negatives "cancel" out, but for "odd" roots there is only one answer (e.g. cube root of 8 = 2 BUT not -2 (-2 Cubed = 8)... So you can get a "cubed" root of a negative number, but not a "Square" root (well you can but its called an imaginary number!smiley - biggrin.

The reason I use 1 as the value of 0^0 is, it is useful to use that value, and it is the answer that my calculator gives me.smiley - biggrin

Oh, and I'm not sure that introducing an extra number is a legitimate strategem (i.e. e = 2.7182818285....) although I wouldn't rule out natural logs (I haven't found them useful yet though!) smiley - winkeye


42!

Post 38

Argon0 (50 and feeling it - back for a bit)

WHOOPS - that should read ....(-2 cubed = -8)..... Don't know what happened to that negative!!!!


42!

Post 39

Gnomon - time to move on

Personally, I would rule out any use of letters at all: I don't think that log, sqrt and e should be used. I would restrict all this to + - * / ^ and (). Possibly ! as well.

But that would spoil the fun.


42!

Post 40

Gnomon - time to move on

My calculator gives an error if I try to calculate 0^0.


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