A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
42!
Farlander Started conversation Jan 6, 2004
hi! er, is
20 x (6/3) + 0! + 0!
valid? it's my researcher number - U206300.
far.
42!
Potholer Posted Jan 6, 2004
That seems fine.
Avoiding '!', you could have:
(20-6)*3+0+0
or
2*06+30+0
42!
Marjin, After a long time of procrastination back lurking Posted Jan 6, 2004
I am not afraid of '!'
((2-0!)+6)*(3*(0!+0!))=42
42!
AK - fancy that! Posted Jan 9, 2004
Never be afraid of !!!!
Is this allowed?
2*"0!6"+(3!*(0!+0!))=42
?
with "0!6" being 1 (0!( and 6 together, or 16?
42!
Marjin, After a long time of procrastination back lurking Posted Jan 9, 2004
Can't see how this will make 42
42!
AK - fancy that! Posted Jan 9, 2004
Oi! You're right! its 44!
nevertheless, is that allowed, you think?
42!
Argon0 (50 and feeling it - back for a bit) Posted Feb 4, 2004
Nah, don't reckong 'tis....
But welcome anyway Farlander to the infamous Mythical Knights of the DoQuaDecagonic table!
Key: Complain about this post
42!
- 1: Farlander (Jan 6, 2004)
- 2: Potholer (Jan 6, 2004)
- 3: Marjin, After a long time of procrastination back lurking (Jan 6, 2004)
- 4: AK - fancy that! (Jan 9, 2004)
- 5: Marjin, After a long time of procrastination back lurking (Jan 9, 2004)
- 6: AK - fancy that! (Jan 9, 2004)
- 7: Argon0 (50 and feeling it - back for a bit) (Feb 4, 2004)
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