A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]

Not all U numbers can be so manipulated.

Post 1

Math - Playing Devil's Advocate

The proof is Jim Lynn U6smiley - tongueout

Math


Not all U numbers can be so manipulated.

Post 2

six7s


However, as Tango pointed out in *Multiple numbers* F64903?thread=234022, adding 4,294,967,296 (2^32) to any U-number will link to the same space

Therefore:

*Normal* U-number: U6
*Additional* U-number: U4294967302

4294967302 ==>> many possible 42isms

such as...

[( 4 + 2 - 9 + 4 ) * 6 * 7 ] + [ 3 * 0 * 2 ] = 42 smiley - smiley

six7s smiley - winkeye


Not all U numbers can be so manipulated.

Post 3

Argon0 (50 and feeling it - back for a bit)

Also each User number can be padded out to 6digits (or more probably) with the addition of leading 0s.... This means that even the italics can be 42'd/...

(smiley - erm

U000006 = ((0!+0!+0!)! + 0! + 0) x 6 = 42


Not all U numbers can be so manipulated.

Post 4

six7s

Experiment:

does 2^64 do the same thing?

U6
smiley - spacesmiley - space 6 + 18,446,744,073,709,551,616
smiley - spacesmiley - space ==>> U18446744073709551622 ??


Not all U numbers can be so manipulated.

Post 5

Argon0 (50 and feeling it - back for a bit)

Blimey it does too.... How about 2^42....

That'd be:

4398046511104+6 = U4398046511110


Not all U numbers can be so manipulated.

Post 6

Argon0 (50 and feeling it - back for a bit)

as...

So mine would be: U4398046588184


Not all U numbers can be so manipulated.

Post 7

Argon0 (50 and feeling it - back for a bit)

Wahay that works too....smiley - coolsmiley - geeksmiley - cool

Oh, and how comes between the 2nd to last and the last posting I just made, the system thought I'd logged out (it didn't recognise me!), but when I clicked on Sign in nothing happened - except I (eventually) got redirected back to my user space!!!!
smiley - grr




Not all U numbers can be so manipulated.

Post 8

AK - fancy that!

Note: It is my guess that the reason this thing with the unumbers happens is that 2^32 is the maximum value for an variable in the programming or something and after that it wraps back around. I'm not nearly sure though but this seems to be a reasonable guess, as in C++ its, I believe, 2^31 for integers and considerably more for other variable types. no reason why perl or pascal or whatever wouldn't do this too...


Not all U numbers can be so manipulated.

Post 9

AK - fancy that!

oh, and about nto all u numbers being able to be manipulated...

U1=invtan(0!)-0!-0!-0-0-1 or the like... it'll do almost all the low ones...


Not all U numbers can be so manipulated.

Post 10

Argon0 (50 and feeling it - back for a bit)

Quite...


Not all U numbers can be so manipulated.

Post 11

AK - fancy that!

I've myself don't beleive I've ever seen a calculator that does invtans... is whoever should be sure about it sure about it? that invtan(1)=45?


Not all U numbers can be so manipulated.

Post 12

Argon0 (50 and feeling it - back for a bit)

Windwos Calc does InvTans ... Put 1 in then click on the INV tick box, and hit Tan...


Not all U numbers can be so manipulated.

Post 13

Argon0 (50 and feeling it - back for a bit)

Ahm taht's in Scientific Mode...


Not all U numbers can be so manipulated.

Post 14

AK - fancy that!

oho! yes it does! smiley - wow


Not all U numbers can be so manipulated.

Post 15

Argon0 (50 and feeling it - back for a bit)


Not all U numbers can be so manipulated.

Post 16

Cool Old Guy (ex-SockPuppet) Trying not to post for the next 200 days !

Cool old Guy smiley - cogs calculating
"Does not work anymore smiley - sadface

Current we have a truncate to 2^31-1 = 2147483647

Or any U number higher then 2^31-1 will render to < U2147483647 >

NB current New this week is < U15001293 >"


Not all U numbers can be so manipulated.

Post 17

Argon0 (50 and feeling it - back for a bit)

So, back in 2015 we had over 15,000,000 registrations? Wow... (ah, does that include all the Beeb registrations?)

anyway: U15001293 = [(15 + 0 + 0) * (2+1)] - (9/3) = 42!


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