A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
I am a true researcher.
Milla, h2g2 Operations Started conversation May 8, 2004
At least I like to believe so. Please verify.
with humble regards,
tjing
Milla
I am a true researcher.
Jeremy (trying to find his way back to dinner) Posted May 8, 2004
1*5-3+6*6+4 = 42.
That's a nice one. Single digits with no brackets 
Jeremy
I am a true researcher.
Milla, h2g2 Operations Posted May 9, 2004
Thanks! It took me a while to get round and actually do the math, but it turned out OK. 
But I haven't made any real contribution to the guide, so maybe I don't qualify as a true researcher anyway...
tjing
Milla
I am a true researcher.
Jeremy (trying to find his way back to dinner) Posted May 9, 2004
You have already made the greatest contribution of them all: *YOURSELF*
That's the only thing that really counts.
Jeremy
I am a true researcher.
AK - fancy that! Posted May 10, 2004
I wanna go at yours...
153664
(15-3)*6-(6!/4!)=42. (I hope)
I am a true researcher.
Jeremy (trying to find his way back to dinner) Posted May 11, 2004
Perfect. You could even leave out the second pair of brackets ...
A good thing to check out your calculation is Google, believe it or not.
Just enter "(15-3)*6-6!/4!" into google and see what happens ...
Jeremy
I am a true researcher.
Milla, h2g2 Operations Posted May 12, 2004
Thanks Jeremy!
I'll contribute more of myself when I get around to it then!
Tjing
Milla
I am a true researcher.
Potholer Posted May 13, 2004
If you wanted a few others to choose from, my 42-solver program found an unusually large number of different solutions just using +-* and /, among which were:-
1/5*3*(66+4) (or 1/5*3*(6+64) )
(1*5/3+6)*6-4
1-5-3*6+64
1-5+36+6+4
(1+5)/3+6*6+4
1+5-(3-6-6)*4
1+5+3*6*(6-4)
15*3-6/(6-4)
15-3+6+6*4
(1+5)*(3+6-6+4)
(1+5-3)*6+6*4
1+53-6*(6-4)
I am a true researcher.
Not him Posted Jul 3, 2004
I can probably find one of these:... for 247749 it would be 2+4+(7*7)-4-9 does that suit?
are there any other obvious ones I should know about?
I am a true researcher.
Megan - another transient astronomer Posted Jul 3, 2004
Ah, the things you can find on H2G2 when you're bored...
(-1*6)+5-5+48 = 42
Megan
Key: Complain about this post
I am a true researcher.
- 1: Milla, h2g2 Operations (May 8, 2004)
- 2: Jeremy (trying to find his way back to dinner) (May 8, 2004)
- 3: Milla, h2g2 Operations (May 9, 2004)
- 4: Jeremy (trying to find his way back to dinner) (May 9, 2004)
- 5: AK - fancy that! (May 10, 2004)
- 6: Jeremy (trying to find his way back to dinner) (May 11, 2004)
- 7: Milla, h2g2 Operations (May 12, 2004)
- 8: Potholer (May 13, 2004)
- 9: Not him (Jul 3, 2004)
- 10: Megan - another transient astronomer (Jul 3, 2004)
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