A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]

30753 solved

Post 1

Caveman, Evil Unix Sysadmin, betting shop operative, and SuDoku addict (Its an odd mix, but someone has to do it)

Assuming I can use brackets, then (3+0)x7x(5-3)=42
That's been bugging me for years. I feel like I've solved Fermats last theorum! Time to update my homepage, which currently reads something like "3 + 0 + (7 x 5) + 3 = 42, for large values of 41", with a footnote to the effect that "Next time, I'll have one from the top, and five small ones please Carol", which is of course a reference to Countdown (A UK Channel 4 quiz show) (French readers may substitute Des Chiffres et des lettres) (See A1105443 if you need to find out)


30753 solved

Post 2

Marjin, After a long time of procrastination back lurking

"3 + 0 + (7 x 5) + 3 = 42" is almost correct as it counts up to 41.smiley - erm
"3 + 0! + (7 x 5) + 3 = 42" is.smiley - ok


30753 solved

Post 3

Potholer

According to my program, which is pretty good (though not infallible), (3+0)*7*(5-3) is the only solution just using +-*/, unless the rather inelegant -30+75-3 is allowed (I have an aesthetic objection to leading '-' signs.)


30753 solved

Post 4

Argon0 (50 and feeling it - back for a bit)

Really? I could never have told...


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