A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]

my 42

Post 1

pedboy

researcher number U200417.

(2*4)*(1*7)=

pedboy® U200417


my 42

Post 2

pedboy

hehe, try again.

(2+0+0+4)x(1x7)=42

pedboy® U200417


my 42

Post 3

AK - fancy that!

200417

(2*0*0)+4+invtan(1)-7=42

((2+0!)!+(4*0*1))*7=42

((sqrt(2))^(0!+0!)+4)*1*7=42

these also work


my 42

Post 4

Potholer

2*(0+0+4+17)


my 42

Post 5

Argon0 (50 and feeling it - back for a bit)

Welcome to the s of the Mythical DoQuaDecaGonic table...


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