h2g2 The Hitchhiker's Guide to the Galaxy: Earth Edition

oh yeah I forgot...


{x=y-4z
x^x=y+(z/y)
x^2=y+z+3x+2x
xyz=-144}
x+y+z=-4
zx
x^2%(|-z|+(1/2x)+6)=3}

[x, |y|, |z-y|, ((1/x)*z^2)/y, x/x, (x^x)/-y+(1.5x), 4,1]

ooc:don't make them too hard...you're probably better at this than I am... and I hope those all work out right, in advance if they don't

git


x=2, y = 1 or -6, z=-.25 or -2.5

also I can't see any scenario where both x and z are less than y BUT I can see a scenarios where z<y<x

So z is -.25 y is 1 and x is therefore 2

You what?
<?>
one p...<?>
0.03125<?>
Is that then?
Well?

oops

[5,7,3]

What happens in here then <?>
Can anyone join in if they desire <?>
Can I play <?>

Aren't you already?
Should you have included some numbers for us to play with?
[3,11,6]

you say three <?>
So is this how this version of the game works then <?>
Do I leve three numbers yes <?>

(4,8,12).

Could it be more?
Is there the possibility it could be less?
Or, even, could it, maybe, be exactly the same number of numbers?

[3,6,1,Invtan(1)-25]

I knew I wouldn't be able to get that thing to work out right... it was supposed to e something like z=-12 x=2 and y= something. I dunno

Should I be <?>
DO you think I am really <?>
Eh?
Considering its what it seems to be in the 42sims, is invtan(1) =45 since it is not on my calculators?<?><?><?>

y should have equaled 6 I think... and for the numbers...



[(2^10-3^6-2(5^3)-5^2), 1,17,6!/5!]

and finally, xz wasn't wrong because z is negative... something else may have been wrong tohugh... perhaps z<x<y would be better but it would have been easier...

if x=2, y=1 and z= -anything, then xz is definitely wrong...

, and if y=-6 then xz is defintely wrong, it should be x>y<z...

Blimey, does it not get very difficult when you start throwing in algebra, Simultaneous equations, AND quadratic equations, or what?
Referee?
Would it be a good idea to have an impartial observer run their eyes across algebraic solutions?
Otherwise will there be a fight?

[6,9,11]

xz... 1-6 meaning that one and -6 are both less that 2... which they are...2 is greater than either of them...

Is there a chance for a "referee"
Or could we simply give up *most* of the maths?
But if we do can we leave, occasionally, a few, maybe?

[2,2,6,6,7]

that's be right if z was -6 and not y

Two two?
Six Six?
Shall we continue with it occasionally?
Instead of every other time?
Would it be shameful if we didn't?

[11, 6, 8, 3]

Ok... thats moer or less resolved

Is it the questions that you want us to continue with<?> <?><?><?>

Do I think we should continue<?>
//
Why should I choose if it is shameful?
Is that *w*ork*<?><?><?>


[8,7,6]

what the hell are you going on about?
is this unfair for the mathematically illiterate?
does anyone else agree with me?

(21, 2, 5)

Do you think someone like me could possibly agree with your questino after the.. wrong... complicatd thng I posted earlier?
Unfair,eh?
It is, is it not?

[15,12,9,6,3,7/2]

How am I meant to come up with six completely different questions in a row?
I mean is one fifteen word question not enough for you people?
How deep am I required to go into Insanity?
Should I purchase a diving suit?
Or a SpaceSuit?
Or Maybe a Subma?