A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
I think I've done it!
U521150 Started conversation Dec 1, 2003
I think I've done it! (well, DUH)
Unumber: U521150, I think 
Ok, here goes...
-5 - 3 + ArcTan(1) - 1 + 5 - 0 = 42 
Has anyone got a more elegant way of doing it? 
I think I've done it!
AK - fancy that! Posted Dec 1, 2003
yes.
(5+2)*1*(1+5)=0
unless the arctan of one is 46 I think you need that last -0 to be a +0!
I think I've done it!
U521150 Posted Dec 1, 2003
to you, mr brains!
is that meant to be a = though? Call me an idiot, wouldn't it be - or + 0 then =42?
Oh, this makes me so glad I gave up Maths!
I think I've done it!
U521150 Posted Dec 1, 2003
So:
(5*2)*1*(1+5)=42
And the 0 can just go as ...+5) - 0 = 42
Right?
*phew*
I think I've done it!
AK - fancy that! Posted Dec 1, 2003
oh... I see now... yeah just put a plus or minus 0 at the end.
No, what I really meant was
-5-3+ArcTan(1)-1+5+ 0!=42
instead of -5-3+ArcTan(1)-1+5 - 0 =42
arctan(1) does equal 45 does it not?
or -5-3+Arctan(1)*1+5+0=42
I think I've done it!
Potholer Posted Dec 2, 2003
For no-bracket solutions:
5*-2+1+1+50
5-2-11+50
52-11+5^0
I think I've done it!
AgProv2 Posted Dec 3, 2003
U538194
5 x 8 = 40
-3 = 37
+9 = 46
-4 = 42
42/1 = 42
There, that looks about right!
Thirty seconds, including proof-reading!
I think I've done it!
AgProv2 Posted Dec 3, 2003
Apologies. Too much watching "Countdown" and too little time reading the rules that apply here.
This has been referred to me
5x3)-8-1+(9x4)=42.
I think I've done it!
U521150 Posted Dec 6, 2003
It's my Unumber, 521150 not 531150 (says at the top, up there 
). Don't know where the 3 came from!
I think I've done it!
Argon0 (50 and feeling it - back for a bit) Posted Feb 2, 2004
Welcome AgProv and Feuile to the Knights of the DoQuaDecagonic table.
I think I've done it!
Argon0 (50 and feeling it - back for a bit) Posted Feb 3, 2004
s'alright! Hopefully I'll have a badge soon(ish)..
I think I've done it!
Argon0 (50 and feeling it - back for a bit) Posted Feb 4, 2004
Another obvious 42ism could be
52 - (1+1)*5 + 0 =42
Key: Complain about this post
I think I've done it!
- 1: U521150 (Dec 1, 2003)
- 2: AK - fancy that! (Dec 1, 2003)
- 3: U521150 (Dec 1, 2003)
- 4: AK - fancy that! (Dec 1, 2003)
- 5: AK - fancy that! (Dec 1, 2003)
- 6: U521150 (Dec 1, 2003)
- 7: AK - fancy that! (Dec 1, 2003)
- 8: Potholer (Dec 2, 2003)
- 9: AgProv2 (Dec 3, 2003)
- 10: AgProv2 (Dec 3, 2003)
- 11: Jeremy (trying to find his way back to dinner) (Dec 5, 2003)
- 12: U521150 (Dec 6, 2003)
- 13: Argon0 (50 and feeling it - back for a bit) (Feb 2, 2004)
- 14: U521150 (Feb 2, 2004)
- 15: Argon0 (50 and feeling it - back for a bit) (Feb 3, 2004)
- 16: U521150 (Feb 3, 2004)
- 17: Argon0 (50 and feeling it - back for a bit) (Feb 4, 2004)
- 18: U521150 (Feb 4, 2004)
- 19: Argon0 (50 and feeling it - back for a bit) (Feb 5, 2004)
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