A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
oops...
Jeremy (trying to find his way back to dinner) Posted Feb 26, 2003
Why not
(2+1)*(7+0+0+7) = 42 ?
That's one of the single digit, no sqrt, no trigonometry, no faculty solutions (no brackets would be the holy grail 
)
Jeremy
My number
Jeremy (trying to find his way back to dinner) Posted Feb 27, 2003
Looks absolutely perfect ... 
My number
Argon0 (50 and feeling it - back for a bit) Posted Oct 17, 2003
Welcome, Found and Starch! to the Mythical s of the DoQuaDecaGonic table 
My number
Mythical DoQuaDecaGonic table Posted Oct 17, 2003
Can not find knight 'Found'
U219072
(21+(9*0*7))*2
(2+19+0*7)*2
awaiting approval
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Argon0 (50 and feeling it - back for a bit) Posted Oct 22, 2003
I dind't even check Found's one... 
...
Ho- Hum
MDQDGT...
And welcome again Found...
Key: Complain about this post
Me number!
- 1: Starch! (Jan 25, 2003)
- 2: Starch! (Jan 25, 2003)
- 3: Starch! (Jan 25, 2003)
- 4: Jeremy (trying to find his way back to dinner) (Feb 26, 2003)
- 5: Found (Feb 26, 2003)
- 6: Jeremy (trying to find his way back to dinner) (Feb 27, 2003)
- 7: Found (Feb 27, 2003)
- 8: Argon0 (50 and feeling it - back for a bit) (Oct 17, 2003)
- 9: Mythical DoQuaDecaGonic table (Oct 17, 2003)
- 10: Argon0 (50 and feeling it - back for a bit) (Oct 22, 2003)
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