A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
Could you try mine... Please :)
Just Justin... (ACE) Started conversation Aug 16, 2002
I'm not sure if you can use the numbers more then once...
but here's mine 200310 
Could you try mine... Please :)
Just Justin... (ACE) Posted Aug 16, 2002
Also, if you want, you can put my page up as well
Thanks 
Could you try mine... Please :)
six7s Posted Aug 16, 2002
InvTan(2-!0) + 0 - 3 * 1 + 0 = 42
PS JJ, have you seen A592049 <?>
Could you try mine... Please :)
Argon0 (50 and feeling it - back for a bit) Posted Dec 8, 2002
200310....
OR without the (dubious) InvTan....
(2+0!)! x (0+3!+1+0) = 42
Could you try mine... Please :)
Argon0 (50 and feeling it - back for a bit) Posted Jun 10, 2003
No Problemo...
Could you try mine... Please :)
Potholer Posted Sep 4, 2003
Or, using only one factorial operator
2+((00)!+3)*10 => 42
(20+0!)*(3-1-0) => 42
Could you try mine... Please :)
Argon0 (50 and feeling it - back for a bit) Posted Sep 30, 2003
OOOOOgh Potholer you clever matriculator you....
Could you try mine... Please :)
AK - fancy that! Posted Sep 30, 2003
*mumbles*has some program...very useful...
Could you try mine... Please :)
Argon0 (50 and feeling it - back for a bit) Posted Oct 3, 2003
There's actually a prog on the web somewhere - it might be off of PotHoler's place, I can't remember...
Key: Complain about this post
Could you try mine... Please :)
- 1: Just Justin... (ACE) (Aug 16, 2002)
- 2: Just Justin... (ACE) (Aug 16, 2002)
- 3: six7s (Aug 16, 2002)
- 4: Argon0 (50 and feeling it - back for a bit) (Dec 8, 2002)
- 5: Just Justin... (ACE) (Dec 9, 2002)
- 6: Argon0 (50 and feeling it - back for a bit) (Jun 10, 2003)
- 7: Potholer (Sep 4, 2003)
- 8: Argon0 (50 and feeling it - back for a bit) (Sep 30, 2003)
- 9: AK - fancy that! (Sep 30, 2003)
- 10: Argon0 (50 and feeling it - back for a bit) (Oct 3, 2003)
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