A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]
Adhemar = 42 = Adhemar = 42 = Adhemar = 6 x 9
Adhemar Started conversation Jun 1, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
1x7x6 + 0x5x0 = 42 (Note the symmetry in the mathematical operators)
-17 + 60 - 5^0 = 42
(-1+7) x (6-0!+5-0!) = 6 x 9
... = Adhemar = 42
Adhemar Posted Jun 2, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
And getting a truer (more true) and truer (more true) Researcher
1! x 7! x (6x0)! / 5! x 0!
... = Adhemar = 42
Adhemar Posted Jun 2, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
The more I find, the uglier they become.
-1-7 + 6x0 + 50 = 42
... = around Adhemar = 42
Adhemar Posted Jun 2, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
The standard function round isn't on every Calculator.
This one (number 6) has a decimal comma (decimal point) in it.
round[exp(1) + 7,60x5 + 0!] = 42
... = still around Adhemar = 42
Adhemar Posted Jun 2, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
And since I'm using the round standard function and the decimal comma (decimal point), here's number 7, the best one yet (although number 1 with symmetry in its mathematical operators was good as well), and I'm probably going to stop here-after:
round[sqrt(1760,50)] = 42
How about that?
... = still around Adhemar = 42
Adhemar Posted Jun 2, 2001
http://www.bbc.co.uk/h2g2/guide/U176050 - Adhemar, Researcher 176050
sqrt(1760,50) isn't exactly 42 - that's why I use ther round standard function.
However if you round off the difference until 3 decimal digits behind the comma (point) you get
42 - sqrt(1760,50) is approximately 0,042
... = still around Adhemar = 42
Oengus (1+7-5)*(5+4+5) Posted Jun 3, 2001
You lost me on the second post. My brain feels like mush. Please stop! 
Adhemar stops
Adhemar Posted Jun 3, 2001
I obviously lost you on the second post. In posting 5 I said I was (probably) going to stop. And I am going to stop. At least I intend to.
Adhemar stops
Oengus (1+7-5)*(5+4+5) Posted Jun 3, 2001
Ah, but good intentions pave the road to hell.
Adhemar goes on
Adhemar Posted Jun 3, 2001
I know, and it's quite convenient, 'cause I am going in that direction.
Adhemar 
176050
Other users = 42
Adhemar Posted Jun 4, 2001
One more comment on round[sqrt(XXXX,XX)]
This works for all users with user number between
172225 = 415² (http://www.bbc.co.uk/h2g2/guide/U172225) and
180624 = 425²-1 (http://www.bbc.co.uk/h2g2/guide/U180624 - isn't a Researcher yet).
Other users = 42
Argon0 (50 and feeling it - back for a bit) Posted Jun 4, 2001
But that'd be cheating....
Cheating.
Argon0 (50 and feeling it - back for a bit) Posted Jun 5, 2001
You mean goes 1 thru 5 not posts 1 thru 5 don't you.
And, Yes they are fine.
Key: Complain about this post
Adhemar = 42 = Adhemar = 42 = Adhemar = 6 x 9
- 1: Adhemar (Jun 1, 2001)
- 2: Adhemar (Jun 2, 2001)
- 3: Adhemar (Jun 2, 2001)
- 4: Adhemar (Jun 2, 2001)
- 5: Adhemar (Jun 2, 2001)
- 6: Adhemar (Jun 2, 2001)
- 7: Oengus (1+7-5)*(5+4+5) (Jun 3, 2001)
- 8: Adhemar (Jun 3, 2001)
- 9: Oengus (1+7-5)*(5+4+5) (Jun 3, 2001)
- 10: Adhemar (Jun 3, 2001)
- 11: Adhemar (Jun 4, 2001)
- 12: Argon0 (50 and feeling it - back for a bit) (Jun 4, 2001)
- 13: Adhemar (Jun 4, 2001)
- 14: Argon0 (50 and feeling it - back for a bit) (Jun 5, 2001)
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