A Conversation for The Myth Of 42 [(5-3+0+5) * (6+0) = 42]

U175557

Post 1

Monkey's Uncle

555? Aww, that must be fake! smiley - winkeye

Anyway, here's mine (I was feeling negative when I worked this out)

-1-7+(-5*5*(5-7))

Is that about right? And fortunately there wasn't SOHCAHTOA in sight.


U175557

Post 2

Mund

There are surely some numbers which cannot be reduced to 42 using the operations which we are allowed. Can anyone think of an arithmetical operation which can derive 42 from 100000?


U175557

Post 3

HenryS

You'd probably have to resort to invtan(1)-0!-0!-0!+0+0 = 42
though invtan feels like a bit too much of a cheat unless its absolutely necessary, and requires youre working in degrees rather than radians. I can't quite see any other way to do it.


U175557

Post 4

HenryS

Or...you can also recall that in very special circumstances, 6 x 9 = 42, in which case:

(10 - 0!) x ((0! + 0! + 0!)!) = 42

Just thought up an alternative for the notorious U109000 which doesn't use this extreme trick, but gave me the idea:

(-1-0!+9) x ((0! + 0! + 0!)!) = 42


U175557

Post 5

Mund

I'm no mathematician, so what's the justification for 0! being 1? After all, if 0! = 1! then 0 = 1, a proof which I remember as the holy grail for the maths nerds at school.


U175557

Post 6

Mund

And what's an invtan? I've been wandering the maths dictionaries of the web for half an hour, and I can't find it.


U175557

Post 7

HenryS

0! = 1! does not imply that 0 = 1, just as (for example) 3^2 = 9 = (-3)^2, but this doesn't mean that 3 = -3

0! is defined to equal 1 for reasons of consistency. I can't really give you a non-mathematical reason why it's defined that way - best I can do is this:

n! is the number of ways of choosing n objects in order, so for example, there are 3! = 6 ways to choose an order for the letters a, b and c:

abc
acb
bac
bca
cab
cba

This works for all n bigger than 0: there are 2 ways to choose an order for 2 objects, and 1 way to choose an order for
one object. Now how many ways are there of choosing an order for 0 objects? Well, maybe you could claim 0 ways, but mathematicians would say 1 way (strictly they would say that the number of permutations (bijections) on a set with no elements is 1).


U175557

Post 8

HenryS

invtan is the inverse of the tan function. Look up tan and there ought to be a reference to it. Also known as tan^(-1) or arctan.


U175557

Post 9

Argon0 (50 and feeling it - back for a bit)

Thank you HenryS - ably overfilling my Shoes in my enforced absence!!! smiley - biggrin

I will add you (U175557) to the list of people to add.... Check the page again in a couple of days...


U175557

Post 10

Monkey's Uncle

Cool beans! Danke.


U175557

Post 11

Future World Dictator (13)

I put 109000 = 10 * (sqrt(9) + 0!) + 0! + 0! up ages ago. Obviously someone whose name may or may not end in a number didn't see it smiley - smiley.

And since the Guide treats U000013 as the same as U13 you can do ((0! + 0! + 0! + 0)! + 1) * 3!.

U100000 is a little harder. How about R((1 + 0! + 0! + 0! + 0 + 0)!) = R(24) = 42, where R(x) is the well-known Reversethedigits function. Or S(1 + 0! + 0! + 0!, 0! + 0!) = S(4, 2) = 42, where S(x, y) = xy is the equally well-known Stickthemtogether function.


U175557

Post 12

Argon0 (50 and feeling it - back for a bit)

smiley - erm admission - I've never seen that version of the 109000 before.....

So The guide treats U000013 the same as U13 and thus U000281 as U281???

I will check - if so it lets a few people (italics) off the hook!

Only way I can get U100000 to = 42 is using invtan using standard Calculator commands.... But, if we start using Excel functions things'll just start getting silly(er).....


U175557

Post 13

Future World Dictator (13)

ie if you point your browser at U000013 you end up at the same place as if you point it at U13.

Quite handy smiley - winkeye


U175557

Post 14

Argon0 (50 and feeling it - back for a bit)

Same with Abi - U000281...


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