h2g2 The Hitchhiker's Guide to the Galaxy: Earth Edition

I did check your page only five minutes ago... but my page has changed a lot over the last few hours

I changed it just slightly, about three minutes ago. And yes, yours has changed quite a bit. I'm now torn between reading those articles (I happen to be quite interested in AI) and doing my calculus homework, which I paused in the middle of about an hour and a half ago.

Well the calculus NEEDS to be done ofcourse (if you were me, you wouldn't have much trouble with it, by the way), but my articles can wait for a while... Although I'd LOVE to have your opinion about them, ofcourse.

Oh, so now you have to make me feel even worse about it by rubbing in my face the fact that this is the first math class I've ever had trouble with. . And it doesn't _need_ to be done until 11 tomorrow, and I've only got about half an hour's worth left....(rationalize, rationalize)

Oops, *now singing "didn't mean to make you cry"*
What is the calculus about at the moment? Maybe I can be of help?
(maybe I'll have trouble translating my knowledge into English, being Dutch and all... but I'm always willing to try)

Well...do you know the radius of convergence for the power series F(z)=(sum as n goes from 0 to infinity) f-sub-n times x to the n, where f-sub-n denotes the nth Fibonacci number? And then can you prove that F(z)=1/(1-z-z^2), and after that can you expand F(z) in terms of partial fractions, and _then_ expand it into two power series?

"carry on, carry on...nothing really matters"

BLAST! I didn't expect you to ask for miracles!

Maybe part of it could be done however not on such short notice), but i'm afraid my understanding of the english gibberish is too fragmented to be of much help. Geez... This is horrible...

It's okay, I'll work it out eventually. Meanwhile, looks like I gotta go.

Ok, we'll meet again soon, I hope

Is 'the radius of convergence for the power series F(z)=(sum as n goes from 0 to infinity) f-sub-n times x to the n, where f-sub-n denotes the nth Fibonacci number? And then can you prove that F(z)=1/(1-z-z^2), and after that can you expand F(z) in terms of partial fractions, and _then_ expand it into two power series?' something to do with making tea? If it is then *holds up hand* I know, miss

Unfortunately, no. Although god knows I'd rather be making tea....

and I don't even like tea....

Ahhh

so this is the place to get equations solved:
could you factorize 5x^2 - 7x - 6
?

OK.

'5x^2 - 7x - 6 = a 33% free packet of chocolate digestives'

and

'5x^2 - 7x - 6 = half a polo'

as factorials come out with two numbers, don't they? The first is obviously more suitable to the chocaholics amongst us (or, as they're more affectionately known, 'What a bunch of Wonkas' ) Of course, if the equasion ended with a 5 instead of a 6, you'd get a 40% free packet of chocolate digestives, though seeing as the difference it would have on the polo would be negligible the latter answer would still be half a polo. This would remain the same for all numbers up to 9, whereupon it would either be a 'part-broken polo' (9-11), a whole polo (12) or a fraction of a polo packet (13 or above). Dividing the 7 by -6 instead of multiplying it would result in fruit polos while turning the entire equasion round would result in a black hole.

I believe that works out to (5x+3)(x-2).

*gives milk*

Chocolate milk?

Hmmm, the best of both worlds... chocolate AND milk

But what about steak?

There's neither chocolate nor milk in a steak, I'm afraid...
If the steak is well done, then get me three of them.