A Conversation for The Euler Equation
Fermat
x25 Started conversation Jun 30, 2000
As a request, could you just put up something on Fermat's last theorem
Fermat
Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) Posted Jun 30, 2000
Errm... ok. As long as you don't want more than a very rough outline of the proof. It's 150 pages long so it is a bit much for someone to understand
I will post a link here afterwards.
Can I ask what it is you want to know?
Fermat
x25 Posted Jun 30, 2000
Well, it's like this, if i am not wrong you are talking about the three colour theorem. I am very unsure about this topic and the problem it actually tries to address. Interested in a very rough sketch of the problem and the way the solution approached it (if such a gross simplification is possible). would be very happy with a link that gives a comprehensive view and starts pretty low. This (as you will probably appreciate) is very difficult to obtain on a conventional search engine without a guide. My interest in the problem stems from previous education and an acquaitance.
regards...
Fermat
26199 Posted Jun 30, 2000
I might be getting horribly confused here, but isn't it a four colour theorem? The one which says, basically, that you can colour in any map with four colours so that no same-colour countries touch...
Either way, I'm fairly sure it's got very little to do with Fermat. Fermat's last theorem says that:
a^n + b^n <> c^n where a, b, c are integers greater than 0 and n > 2.
Sorry, using computer notation there: ^ means 'to the power of', and <> means 'does not equal'.
As for how you prove it, I have absolutely no idea
26199
Fermat
Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) Posted Jun 30, 2000
The proof for FLT is quite simple. If you re-arrange the FLT equation, you can obtain an elliptic curve. Ken Ribet (I think) proved Frey's argument that this function (a semi-stable elliptic curve) cannot be modular if it is possible. Thus, by proving Taniyama-Shimura for this set of elliptic curves, you prove FLT.
And it is the 4 colour theorum and that proof required amazing amounts of number crunching on computer.
Fermat
Jim diGriz Posted Jul 1, 2000
Have you read Donald Knuth's fascinating series _The Art of Computer Programming_?
At the start of each book, he has a set of Notes on the Exercises, just to get you used to the kind of difficulty of problems in the text.
Problem 4 right at the beginning of the first volume is:
4. Prove that when n is an integer, n > 2, the equation x^n + y^n = z^n has no solution in positive integers x,y,z.
What a mean man! I mean he doesn't even say that he's asking for a proof of Fermat's Last Theorem!
Just the kind of thing you'd need to tackle in the introduction before you even start the book!
Fermat
Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) Posted Jul 1, 2000
Oh God... there is a name given to twisted people like that. It's "mathematician"
Not that I can complain
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Fermat
- 1: x25 (Jun 30, 2000)
- 2: Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) (Jun 30, 2000)
- 3: x25 (Jun 30, 2000)
- 4: 26199 (Jun 30, 2000)
- 5: Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) (Jun 30, 2000)
- 6: Jim diGriz (Jul 1, 2000)
- 7: Joe aka Arnia, Muse, Keeper, MathEd, Guru and Zen Cook (business is booming) (Jul 1, 2000)
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