This is the Message Centre for Recumbentman
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men
Recumbentman Started conversation Apr 15, 2003
to a tessellate plain come two disparate hordes
to fight to the death in the name of their lords
one faction may triumph or both may be shamed
but no man shows merit and none can be blamed
pawns battle upward and never look back
knights gad about cutting through to attack
bishops adopt contradictory attitudes
rooks set up strongholds enthralling new latitudes
queens go in style with the trappings of fame
kings back their champions to capture the game
unmourned, unenlightened, we shuffle away
to face resurrection when gods stoop to play
men
Rudest Elf Posted Dec 13, 2003
The visit would have been worthwhile for this alone. I find your style graphic and satisfying. Thank you for sharing.
men
Recumbentman Posted Dec 13, 2003
Thank you Researcher 229466, and welcome.
I hope you discover your own hootoo identity soon.
In the meantime might I remark how curious it is: 2 x 29 - 4 - 6 - 6 = 42.
men
Rudest Elf Posted Dec 13, 2003
Yes, but did you know.....
3+4+5+6+7+8+9 = 42 and 9+10+11+12 = 42?
men
Recumbentman Posted Dec 13, 2003
Well no I didn't! Maybe you could help me with 208656. So far the best I have is 20 - 8 + six fives (yes, six) = 42.
Now that I think of it 20+ 8 + 6 + int.(sqr root 5) + 6 = 42 too.
But that's still messy.
men
Recumbentman Posted Dec 13, 2003
That is so neat, it's going in straight away!
Merci, BoƮte aux Jouets!
men
Recumbentman Posted Dec 14, 2003
My own formula for my Researcher number was "twenty minus eight plus six fives (yes, six) equals 42". It relies as I said on a sidestep (repeating 'six' without the repetition entering into the calculation). I had posted it in my Journal, but it had slopped down the page and off the end. Toy Box's superior solution has now been incorporated into my "about me" paragraph. Nothing stranger than that.
men
Rudest Elf Posted Dec 14, 2003
I don't understand why Toy Boxes effort is so cool. There must be a million ways (many more for sure) to reach 42 (I've done it myself!)
men
toybox Posted Dec 14, 2003
I think A530560 explains it all. The point is to get 42 using only the digits appearing in your U-number and in the same order (in your case 2 2 9 4 6 6; Recumbentman had to use 2 0 8 6 5 6 and I had 2 0 8 4 6 4).
Apart from these two constraints, more or less any operation is allowed.
men
Rudest Elf Posted Dec 14, 2003
Thanks for the towel. I must be very lucky! The following was found within minutes:
(2x2)x(root 9)+(4x6)+6=42
Can't find a root....story of my life!
Can one express (2x2) as 2 squared?
men
Rudest Elf Posted Dec 14, 2003
You might prefer:
2/2 + (9-4) + (6x6) = 42
Or...... ( ( (2/2) + (9-4) ) x 6 ) + 6 = 42
Should I look further? I am not a mathematician.
men
Recumbentman Posted Dec 14, 2003
2^2 looks nice if you want a variant on 2x2
You're not a mathematician?? How do you come up with all the formulas then?
men
Recumbentman Posted Dec 14, 2003
OK inspired by your anateur status as a mathematician, I have tried again with my U nimber, and come up with
(2 plus 0) into 86 + 5 - 6 = 42
But is there any mathematical symbol for "into"?
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- 1: Recumbentman (Apr 15, 2003)
- 2: Rudest Elf (Dec 13, 2003)
- 3: Recumbentman (Dec 13, 2003)
- 4: Rudest Elf (Dec 13, 2003)
- 5: Recumbentman (Dec 13, 2003)
- 6: Rudest Elf (Dec 13, 2003)
- 7: toybox (Dec 13, 2003)
- 8: Recumbentman (Dec 13, 2003)
- 9: Rudest Elf (Dec 13, 2003)
- 10: Recumbentman (Dec 14, 2003)
- 11: Recumbentman (Dec 14, 2003)
- 12: Rudest Elf (Dec 14, 2003)
- 13: toybox (Dec 14, 2003)
- 14: Rudest Elf (Dec 14, 2003)
- 15: Rudest Elf (Dec 14, 2003)
- 16: Recumbentman (Dec 14, 2003)
- 17: Rudest Elf (Dec 14, 2003)
- 18: Recumbentman (Dec 14, 2003)
- 19: Rudest Elf (Dec 14, 2003)
- 20: Recumbentman (Dec 14, 2003)
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