A Conversation for Games Room
Nice brainteaser
Rudest Elf Posted Jan 30, 2010
That's very likely to be the answer Czar Dene is seeking. I came up with the same solution a couple of days ago, but dismissed it as being too prosaic.
Nice brainteaser
Dene - specialist in red herrings Posted Jan 30, 2010
Icy is correct to say that it is binary. But I had the broken lines as nil. But I accept your answer. Your turn.
Nice brainteaser
Icy North Posted Jan 30, 2010
How many ways are there of tiling a floor, if your tiles are regular polygons whose sides have to fit edge-to-edge (i.e. no gaps and no skewing them, as with a brick wall).
Nice brainteaser
Icy North Posted Jan 31, 2010
I'll accept either of two answers, but sadly that's not one of them. It is a multiple of one of them, though
Nice brainteaser
Rudest Elf Posted Feb 1, 2010
Surely the number of permutations depends on the number of tiles needed to cover the floor?
If I have 16 square plain white tiles to fit a 4x4 floor, then any of 16 can be placed top left, any of 15 can fit next to it, any of 14 next to that, and so on - I may be wrong (I'm happy to be corrected) but doesn't that amount to 16! (2.09227899 x 10^13)?
On the same basis (and I'm beginning to have serious doubts here ), 100 square plain white tiles would give some 9.33262154 x 10^157 permutations.
The problem is complicated further when you recognise that each tile has 4 edges, and so may be placed 4 ways...
Where *is* Julzes when you need him?
Nice brainteaser
Rudest Elf Posted Feb 3, 2010
If the outermost edges (those touching the walls) have to be straight, then equilateral triangles work; if the edges can be ragged, then hexagons will do the job.
On the other hand, if mixing shapes and/or sizes in the same design is permitted, I'd have to think again (or maybe not ).
On the third hand, neither 2 nor 3 go into 5,505,005...
Nice brainteaser
Rudest Elf Posted Feb 3, 2010
The square is just one type of rectangle, so I suppose I should add rectangles as another shape. BUT 4 doesn't go into 5,505,005 either. Perhaps the answer is five?
Nice brainteaser
Icy North Posted Feb 3, 2010
Rectangles aren't generally regular (only in the case of a square).
Squares, triangles and hexagons are three of the tilings I'm looking for, but I'm also looking for tilings which use more than one type
And the answer isn't 5.
Nice brainteaser
Rudest Elf Posted Feb 3, 2010
Lost patience and went to Google for the answer.
Still, at least we've managed to clarify the question a bit.
Nice brainteaser
Icy North Posted Feb 4, 2010
I'll post it then, and we'll have a footrace for the next puzzle.
As you probably found in your Google search, the classic answer is the set of 11 Archimedean tilings.
Three of these are the regular ones you found, using the same polygon throughout: http://mathworld.wolfram.com/RegularTessellation.html
The other eight use more than one type of polygon: http://mathworld.wolfram.com/SemiregularTessellation.html
But, depending on your definition of tiling, you can define lots of similar ones (a hexagon can be replaced by six triangles, etc). In fact, there is an infinite number.
***
OK, next puzzle, anyone?
Nice brainteaser
Dene - specialist in red herrings Posted Mar 25, 2010
"In two years," said Dad to Roy and Joy, "Joy's age will be three-quarters of Roy's and in 10 years your combined ages will be three-quarters of mine. At the moment the total of your ages is a third of mine."
How old are they?
Nice brainteaser
Rudest Elf Posted Mar 27, 2010
Looks like it's just you and me, Czar Dene . Perhaps you can attract a few more people from the other games threads?
As usual, I don't have a new teaser so I'll just add another clue (hope you don't mind):
The three ages (currently) add up to 40 years.
Nice brainteaser
Icy North Posted Mar 27, 2010
It's a shame we don't have more subscribers
I'll post one, but I'd better solve this one first:
I'll leave the working out to others, but there are three equations in three variables, ages J, R and D, and it all works out to Roy being 6, Joy being 4 and Dad being 30.
OK, here's a new one:
There are an odd number of meerkats in a field. Each meerkat is suspiciously eyeing the nearest meerkat. How do you know that at least one meerkat isn't being watched?
Nice brainteaser
Icy North Posted Mar 27, 2010
... I should also add that the meerkats are a distinct distance apart.
Key: Complain about this post
Nice brainteaser
- 3001: Rudest Elf (Jan 30, 2010)
- 3002: Icy North (Jan 30, 2010)
- 3003: Dene - specialist in red herrings (Jan 30, 2010)
- 3004: Icy North (Jan 30, 2010)
- 3005: Rudest Elf (Jan 31, 2010)
- 3006: Icy North (Jan 31, 2010)
- 3007: Rudest Elf (Feb 1, 2010)
- 3008: Icy North (Feb 1, 2010)
- 3009: Rudest Elf (Feb 3, 2010)
- 3010: Rudest Elf (Feb 3, 2010)
- 3011: Icy North (Feb 3, 2010)
- 3012: Rudest Elf (Feb 3, 2010)
- 3013: Icy North (Feb 4, 2010)
- 3014: Rudest Elf (Feb 4, 2010)
- 3015: Icy North (Feb 4, 2010)
- 3016: Rudest Elf (Feb 4, 2010)
- 3017: Dene - specialist in red herrings (Mar 25, 2010)
- 3018: Rudest Elf (Mar 27, 2010)
- 3019: Icy North (Mar 27, 2010)
- 3020: Icy North (Mar 27, 2010)
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